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These are ostensibly acid-base reactions. For ammonium we could write. NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed. Products formed are; Cu (OH)_2 + HCl - CuCl_2 + H_2O Since CuCl_2 is soluble in water. But; Cu (OH)_2 + HCl - CuCl_2 + H_2O [Not Balanced] Balancing the equation. So this is a propanol derivative: 2-methylpropan-2-ol For isopropyl alcohol , H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so propan-2-ol I think this is right, and I haven't broken any arcane rule. Both names seem to be unambiguous. a. HI (aq) rarr H^ (+) + I^- b. HNO_3 (aq) rarr H^ (+) + NO_3^- c. Ba (OH)_2 (aq) rarr Ba^ (2+) + 2HO^-. Hydrogen iodide is in fact a very strong acid; as is nitric acid , HNO_3 (in fact the former is a stronger acid than the latter!). How about these? (a) With HCN The HCN adds across the α C=O group to form a cyanohydrin. underbrace ( CH _3 COCOOH )_color (red) ( pyruvic acid ) + HCN →. Q&A and Videos that make learning easy. Math, History, Chemistry, Algebra, Calculus, Biology and more. The balanced equation is CH _3 CH _2 COO ^ - + 3S + 4 OH ^ - → CH _3 COO ^ - + HCO _3^ - + 3HS ^ - + H _2 O The reaction is carried out at pH 8, so we must balance in basic solution. Only (C) is fully correct. As you can see, steam typically reacts with alkenes by adding H on one double-bonded atom and OH on the other. But there are two possible choices for which atom gets the single hydrogen atom and which gets the OH group. In some cases like (A) there is a perference (the Markovnikov rule), but the only sure way to get 100% of one product is to have the double bond in. The equation for this is: H^+ (aq)+OH^ (-) (aq)rightleftharpoonsH_2O (l) A common example of a neutralization reaction would be adding hydrochloric acid to aqueous sodium hydroxide. DeltaH = + 12.2 kJ Yes, you are correct. The molar enthalpy of vaporization, or simply the enthalpy of vaporization, tells you the enthalpy change that occurs when one mole of a substance goes from liquid at its boiling point to vapor at its boiling point. Since heat is needed in order for a substance to undergo a liquid - vapor phase change, the enthalpy of vaporization, DeltaH_ vap , will.

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